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6x^2+25x-27=0
a = 6; b = 25; c = -27;
Δ = b2-4ac
Δ = 252-4·6·(-27)
Δ = 1273
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{1273}}{2*6}=\frac{-25-\sqrt{1273}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{1273}}{2*6}=\frac{-25+\sqrt{1273}}{12} $
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